Solutions

In[79]:=

(*1*)Limit[Sin[x]/x, x0]

Out[79]=

1

In[80]:=

(*2*)Limit[Sqrt[1 - x^2]/Sqrt[1 - x], x1]

Out[80]=

2^(1/2)

In[81]:=

(*3*)Limit[(1 + 1/n)^n, nInfinity]

Out[81]=



In[82]:=

(*4*)Limit[(2^(4n + 1) (n !)^4)/((2n + 1) ((2n) !)^2), nInfinity]

Out[82]=

π

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